c^2-11c+28=0

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Solution for c^2-11c+28=0 equation: 


Simplifying
c2 + -11c + 28 = 0

Reorder the terms:
28 + -11c + c2 = 0

Solving
28 + -11c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(4 + -1c)(7 + -1c) = 0


Subproblem 1
Set the factor '(4 + -1c)' equal to zero and attempt to solve:

Simplifying
4 + -1c = 0

Solving
4 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1c = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1c = 0 + -4
-1c = 0 + -4

Combine like terms: 0 + -4 = -4
-1c = -4

Divide each side by '-1'.
c = 4

Simplifying
c = 4

Subproblem 2
Set the factor '(7 + -1c)' equal to zero and attempt to solve:

Simplifying
7 + -1c = 0

Solving
7 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1c = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1c = 0 + -7
-1c = 0 + -7

Combine like terms: 0 + -7 = -7
-1c = -7

Divide each side by '-1'.
c = 7

Simplifying
c = 7
Solution
c = {4, 7}

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